5. Find the minimum distance between the point Q: (4,0,1) and a point on the line \( \vec{r} = \begin{bmatrix} 1 \ -4 \ 2 \end{bmatrix} + t \begin{bmatrix} 1 \ 2 \ -1 \end{bmatrix} \). Use the (not-to-scale) diagram below to get you started. (a) Do it using a combination of vectors and calculus by writing an expression for the distance between Q and any point on the line, then minimizing t. (b) Do it using vectors only by finding the magnitude of a vector perpendicular to the line that ends on Q. Q: (4,0,1) P: (1,-4,2) \( \vec{m} = \begin{bmatrix} 1 \ 2 \ -1 \end{bmatrix} \)
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(a) Using a combination of vectors and calculus: We can write the equation of the line as: r = [1,-4,2] + t[1,2,-1] where r is any point on the line and t is a scalar parameter. Show more…
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