Question

Find the minimum sample size you should use to assure that your estimate of p? will be within the required margin of error around the population p. Margin of error: 0.009; confidence level: 99%; p? and q? are unknown 72 20,465 185 20,464 QUESTION 5 Solve the problem. Find the value of -z?/2 that corresponds to a level of confidence of 96.16 percent. 0.0192 2.07 -2.07 -1.77 QUESTION 6 Determine whether the given conditions justify using the margin of error E = z?/2 ?/?n when finding a confidence interval estimate of the population mean ?. The sample size is n = 8, ? is not known, and the original population is normally distributed. No Yes QUESTION 7 Use the given degree of confidence and sample data to construct a confidence interval for the population mean ?. Assume that the population has a normal distribution. n = 10, x? = 9.8, s = 2.4, 95 percent 8.11 < ? < 11.49 8.41 < ? < 11.19

          Find the minimum sample size you should use to assure that your estimate of p? will be within the required
margin of error around the population p.

Margin of error: 0.009; confidence level: 99%; p? and q? are unknown
72
20,465
185
20,464

QUESTION 5
Solve the problem.
Find the value of -z?/2 that corresponds to a level of confidence of 96.16 percent.
0.0192
2.07
-2.07
-1.77

QUESTION 6
Determine whether the given conditions justify using the margin of error E = z?/2 ?/?n when finding a
confidence interval estimate of the population mean ?.

The sample size is n = 8, ? is not known, and the original population is normally distributed.
No
Yes

QUESTION 7
Use the given degree of confidence and sample data to construct a confidence interval for the population
mean ?. Assume that the population has a normal distribution.

n = 10, x? = 9.8, s = 2.4, 95 percent
8.11 < ? < 11.49
8.41 < ? < 11.19

Show more…

Find the minimum sample size you should use to assure that your estimate of p? will be within the required
margin of error around the population p.

Margin of error: 0.009; confidence level: 99%; p? and q? are unknown
72
20,465
185
20,464

QUESTION 5
Solve the problem.
Find the value of -z?/2 that corresponds to a level of confidence of 96.16 percent.
0.0192
2.07
-2.07
-1.77

QUESTION 6
Determine whether the given conditions justify using the margin of error E = z?/2 ?/?n when finding a
confidence interval estimate of the population mean ?.

The sample size is n = 8, ? is not known, and the original population is normally distributed.
No
Yes

QUESTION 7
Use the given degree of confidence and sample data to construct a confidence interval for the population
mean ?. Assume that the population has a normal distribution.

n = 10, x? = 9.8, s = 2.4, 95 percent
8.11 < ? < 11.49
8.41 < ? < 11.19

Added by Marta G.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Madhur L

04/12/2023

Step 1

Since the confidence level is 99%, the area in the tails is 1 - 0.99 = 0.01. Since the normal distribution is symmetric, we divide this by 2 to get 0.005 in each tail. Using a z-table or calculator, we find that the z-score corresponding to 0.005 in the tail is Show more…

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Find the minimum sample size you should use to assure that your estimate of p̂ will be within the required margin of error around the population p. Margin of error: 0.009; confidence level: 99%; p̂ and q̂ are unknown. 72 20,465 185 20,464 QUESTION 5 Solve the problem. Find the value of -zα/2 that corresponds to a level of confidence of 96.16 percent. 0.0192 2.07 -2.07 -1.77 QUESTION 6 Determine whether the given conditions justify using the margin of error E = zα/2 σ/√n when finding a confidence interval estimate of the population mean μ. The sample size is n = 8, σ is not known, and the original population is normally distributed. No Yes QUESTION 7 Use the given degree of confidence and sample data to construct a confidence interval for the population mean μ. Assume that the population has a normal distribution. n = 10, x̄ = 9.8, s = 2.4, 95 percent 8.11 < μ < 11.49 8.41 < μ < 11.19

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Transcript

00:01 Hello students, on question number 4, they given that the margin of error e is equal to 0 .09 and the confidence interval is 99 percentage.

00:16 Then the p cap and q cap are unknown.

00:24 Now, to calculate the sample size, the formula of margin of error e is z alpha by 2 into square root of p cap into 1 minus p cap divided by n.

00:38 So, to calculate n, the sample formula is z alpha by 2 the whole square p cap into 1 minus p cap divided by e the whole square.

00:51 Now, here the p cap and the q cap is equal to 0 .5.

00:57 So, n is equal to z alpha by 2 into 0 .25 divided by e square or 99 percentage the z alpha by 2 is equal to 2 .575 which is equal to n into 2 .575 square into 0 .25 divided by 0 .009 the whole square.

01:33 Now, which is equal to we get our sample size n is equal to 20464 .89 which is equal to 20465.

01:48 Then for the question number 5, they given that confidence interval as 96 .16 percentage.

02:03 So, alpha is equal to 0 .0384.

02:07 Then the z alpha by 2 which is equal to 0 .0192.

02:17 Now, so p of z less than z 0 .0192 we get 0 .9808 from the z table we get z 0 .0192 is equal to minus 2 .074.

02:42 Therefore, thus minus z alpha by 2 is equal to minus 2 .074.

02:50 Therefore, it is equal to minus 2 .07.

02:54 Then for the question number 6, determine whether the given condition justify the margin of error e is equal to z alpha by 2 into sigma by square root of n when finding a confidence interval estimate for a population mean mu...

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