Question

A. Find the number of even and odd permutations in Sn for n = 1, 2, 3, 4. B. Present the following permutation as a product of non-intersecting cycles for all k: (1 2 3)^k = (1 2 3) ··· (1 2 3) k times

          A. Find the number of even and odd permutations in Sn for n = 1, 2, 3, 4.
B. Present the following permutation as a product of non-intersecting cycles for all k:
(1 2 3)^k = (1 2 3) ··· (1 2 3)
k times

Added by Michelle J.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sri K

08/05/2023

Step 1

This is an even permutation since it can be represented as a product of zero transpositions. So, there are 0 odd permutations and 1 even permutation. For n = 2, there are two permutations: (1 2) and (1)(2). The first one is an odd permutation since it is a single Show more…

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A. Find the number of even and odd permutations in Sn for n = 1, 2, 3, 4. B. Present the following permutation as a product of non-intersecting cycles for all k: (1 2 3)^k = (1 2 3) ... (1 2 3) (k times)