find the number of solutions of x1+x2+x3 = 6 where x1, x2, x3 are integers with x1 greater than or equal to 3, x2 greater than equal to 1 and smaller than equal to 3, x3 greater than equal to 2, and smaller than equal to 5
Added by Kristy W.
Step 1
Since x1 must be greater than or equal to 3, we can start by setting x1 = 3. This leaves us with the equation x2 + x3 = 6 - 3 = 3. Show more…
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