Since the given vectors are linearly independent, they form a basis for the subspace. So, the basis is:
$$
\begin{bmatrix} 1 \\ 0 \end{bmatrix}, \begin{bmatrix} 0 \\ 1 \end{bmatrix}
$$
Now, let's find the orthogonal projection of the vector $\begin{bmatrix} 2 \\
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