Question

Find the partial derivatives of the function $f(x, y) = \frac{1x + 9y}{8x - 2y}$ $f_x(x, y) = \frac{(-74y + 9xy)}{(8x - 2y)^2}$ $f_y(x, y) = \frac{(-74yx + 74x)}{(8x - 2y)^2}$

          Find the partial derivatives of the function
$f(x, y) = \frac{1x + 9y}{8x - 2y}$
$f_x(x, y) = \frac{(-74y + 9xy)}{(8x - 2y)^2}$
$f_y(x, y) = \frac{(-74yx + 74x)}{(8x - 2y)^2}$

Find the partial derivatives of the function
f(x, y) = (1x + 9y)/(8x - 2y)
fx(x, y) = ((-74y + 9xy))/((8x - 2y)^2)
fy(x, y) = ((-74yx + 74x))/((8x - 2y)^2)

Added by George C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Vikash Ranjan

01/08/2022

Step 1

Step 1: To find the partial derivative of f(x,y) with respect to x, we treat y as a constant and differentiate f(x,y) with respect to x. Show more…

Show all steps

Thanks for your feedback!

Find the partial derivatives of the function $$f(x,y) = \frac{1x+9y}{8x-2y}$$ $$f_z(x,y) = \frac{(-74y+9xy)}{(8x-2y)^2}$$ $$f_y(x,y) = \frac{(-74yx+74x)}{(8x-2y)^2}$$