Find the particular solution for the differential equation $$\frac{dy}{dx} = \frac{2x^3}{3y}$$ at $$y(0)=3.$$ Choose the correct answer below. A. $$y = \frac{1}{3}x^4 + 3$$ B. $$y = 3x^3 + 3$$ C. $$y^2 = 3x^3 + 9$$ D. $$y^2 = \frac{1}{3}x^4 + 9$$
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Step 1: Separate variables: $\dfrac{dy}{dx}=\dfrac{2x^3}{3y}\Rightarrow y\,dy=\dfrac{2}{3}x^3\,dx$. Show more…
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