Find the particular solution to the differential equation (dy)/(dx) = xy^2 with the initial cond

Question

Find the particular solution to the differential equation $\frac{dy}{dx} = xy^2$ with the initial condition $(0, \frac{1}{3})$. A $y = \frac{6x^2 + 1}{3}$ B $y = \frac{x^2 + 3}{9}$ C $y = \frac{2}{6 - x^2}$ D $y = -\frac{2}{3} \ln|x| + 1$

          Find the particular solution to the differential equation $\frac{dy}{dx} = xy^2$ with the initial condition $(0, \frac{1}{3})$.
A $y = \frac{6x^2 + 1}{3}$
B $y = \frac{x^2 + 3}{9}$
C $y = \frac{2}{6 - x^2}$
D $y = -\frac{2}{3} \ln|x| + 1$

Find the particular solution to the differential equation (dy)/(dx) = xy^2 with the initial condition (0, (1)/(3)).
A y = (6x^2 + 1)/(3)
B y = (x^2 + 3)/(9)
C y = (2)/(6 - x^2)
D y = -(2)/(3)ln|x| + 1

Added by Lisa F.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Khushbu Rani

05/02/2023

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Step 1: Rewrite the differential equation in the form dy/dx = xy. Show more…

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Find the particular solution to the differential equation dx =xy with the initial condition (, ). A 6x2+1 3 B 2+3 9 C 2 y 6-2 D y= In|x|+1

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Find the particular solution to the differential equation $\frac{dy}{dx} = xy^2$ with the initial condition $(0, \frac{1}{3})$. A $y = \frac{6x^2 + 1}{3}$ B $y = \frac{x^2 + 3}{9}$ C $y = \frac{2}{6 - x^2}$ D $y = -\frac{2}{3} \ln|x| + 1$

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