Find the perimeter of the triangle with vertices A (-2,2,2), B(4,-4,4), and C(7,6,3)
Added by Benjamin J.
Step 1
We can do this using the distance formula for three dimensions, which is: d = sqrt[(x2-x1)^2 + (y2-y1)^2 + (z2-z1)^2] So, the length of side AB is: AB = sqrt[(4-(-2))^2 + ((-4)-2)^2 + (4-2)^2] = sqrt[36 + 36 + 4] = sqrt[76] The length of side BC is: Show more…
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