Find the pH of a 0.350 M aqueous benzoic acid solution. For benzoic acid, Ka = 6.5 * 10^-5. a) 4.64 b) 4.19 c) 2.32 d) 11.68
Added by Juan Manuel B.
Step 1
350 M. At equilibrium, the concentration of C6H5COOH will have decreased by x, and the concentrations of C6H5COO- and H+ will have increased by x. So we can write the equilibrium concentrations as follows: [C6H5COO-] = x [H+] = x [C6H5COOH] = 0.350 - Show more…
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