Find the points of inflection and discuss the concavity of the graph of the function:
Let f(x) be a function whose second derivative exists on an open interval I. Then if f''(x) > 0 for all x in I, then the graph of f is concave up on I. And if f''(x) < 0 for all x in I, then the graph of f is concave down on I. If a tangent line exists at a point where concavity changes, this point is called a point of inflection.
The given function is f(x) = sqrt(x).
The domain of the function is x ≥ 0.
To differentiate the given function with respect to x, perform the derivative of the square root function and write with rational exponents: f'(x) = (1/2)x^(1/2). Take the derivative.