Find the points on the curve where the tangent is horizontal or vertical. If you have a graphing device, graph the curve to check your work. (Enter your answers as a comma-separated list of ordered pairs.) $x = t^3 - 3t$, $y = t^2 - 8$ horizontal tangent $(x, y) = $ vertical tangent $(x, y) = $
Added by Derek O.
Close
Step 1
We are given the parametric equations of the curve: $x = 3t$ and $y = t^2 - 8$. Show more…
Show all steps
Your feedback will help us improve your experience
Sri K and 56 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find the points on the curve where the tangent is horizontal or vertical. If you have a graphing device, graph the curve to check your work. (Enter your answers as a comma-separated list of ordered pairs.) x = t^3 − 3t, y = t^2 − 6 horizontal tangent (x, y) = vertical tangent (x, y) =
Shaiju T.
Find the points on the curve where the tangent is horizontal or vertical. If you have a graphing device, graph the curve to check your work. (Enter your answers as a comma-separated list of ordered pairs.) x = t^3 - 3t, y = t^2 - 8 horizontal tangent (x, y) = vertical tangent (x, y) =
Audrey F.
Find the points on the curve where the tangent is horizontal or vertical. If you have a graphing device, graph the curve to check your work. (Enter your answers as a comma-separated list of ordered pairs.) x = 8 − t2, y = t3 − 48t horizontal tangent (x, y) = vertical tangent (x, y) =
Zhumagali S.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD