$$v(t) = \int a(t) dt = \int -0.01t dt$$
Now, integrate:
$$v(t) = -0.005t^2 + C$$
We are given the initial velocity, v(0) = 10. Use this to find the constant C:
$$10 = -0.005(0)^2 + C$$
$$C = 10$$
So, the velocity function is:
$$v(t) = -0.005t^2 + 10$$
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