Question

Find the position and velocity of an object moving along a straight line with the given acceleration, initial velocity and initial position. Assume units of meters and seconds: a(t) = 20/(t+2)^2; v(0) = 20; s(0) = 10

Name: Find the position and velocity of an object moving along a straight line with the given acceleration, initial velocity and initial position. Assume units of meters and seconds: a(t) = 20/(t+2)^2; v(0) = 20; s(0) = 10
Uploaded: 2023-08-02T00:23:56-08:00
Duration: 3 min 30 s
Channel: William Semus
Description: Find the position and velocity of an object moving along a straight line with the given acceleration, initial velocity and initial position. Assume units of meters and seconds: a(t) = 20/(t+2)^2; v(0) = 20; s(0) = 10

          Find the position and velocity of an object moving along a straight line with the given acceleration, initial velocity and initial position. Assume units of meters and seconds: a(t) = 20/(t+2)^2; v(0) = 20; s(0) = 10

Find the position and velocity of an object moving along a straight line with the given acceleration, initial velocity and initial position. Assume units of meters and seconds: a(t) = 20/(t+2)^2; v(0) = 20; s(0) = 10

Added by Katie W.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert William Semus

08/02/2023

Step 1

Step 1: Find the velocity function v(t) by integrating the acceleration function a(t): a(t) = 7 + 2t v(t) = ∫(7 + 2t) dt = 7t + t^2 + C Using the initial velocity v(0) = 20, we can solve for the constant C: v(0) = 7(0) + (0)^2 + C = 20 C = 20 Therefore, the Show more…

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Find the position and velocity of an object moving along a straight line with the given acceleration, initial velocity and initial position. Assume units of meters and seconds: a(t) = 20/(t+2)^2; v(0) = 20; s(0) = 10