00:01
So, the question is that we have to find out the principal unit normal vector of the curve represented by the vector value function rt is equal to cos of 3t i plus 2 sin 3t j plus k.
00:25
So, we have to find out the unit normal vector.
00:27
So, unit normal vector to find out, so we will find out the first derivative with respect to t.
00:34
So, dy dt of rt.
00:38
So, we will just apply the separation over here.
00:43
So, the dy dt will be separated in each order.
00:46
So, it will be equal to minus 3 sin of 3t i plus 6 cos of 3t j and k has no t term.
01:00
So, it will be equal to 0.
01:01
So, it will be equal to minus 3 sin 3t i plus 6 cos 3t j.
01:11
So, it is r dash of t.
01:16
So, we have to find out the active pi and t is equal to pi...