Question

Find the relative minimum value of f(x,y) = 4x^2 + 2y^2 - xy, subject to the constraint x + y = 28. The relative minimum value is f( , ) = . (Simplify your answers.)

          Find the relative minimum value of f(x,y) = 4x^2 + 2y^2 - xy, subject to the constraint x + y = 28.
The relative minimum value is f( , ) = . 
(Simplify your answers.)

Added by Amy C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

06/30/2023

Step 1

To do this, we take the partial derivatives with respect to x and y and set them equal to 0. ∂f/∂x = 8x - y = 0 ∂f/∂y = 4y - x = 0 Show more…

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Find the relative minimum value of f(x,y)=4x^(2)+2y^(2)-xy, subject to the constraint x+y=28. The relative minimum value is f()=, (Simplify your answers.) Find the relative minimum value of f(,y) = 4x2 + 2y2 -- xy, subject to the constraint + y = 28. The relative minimum value is f= (Simplify your answers.)