00:02
Hi, given a2 as 2 and a3 as minus root 2 for a gp, we have to find it seventh term.
00:10
So general term is given by a .r to the power n minus 1.
00:14
Now, a2 is 2, so this will be equal to ar is equal to 2 and let us take this as 1.
00:20
A3 will be ar square equal to minus root 2.
00:24
Let us take this as 2.
00:25
So 2 divided by 1 gives ar square by arr is equal to minus root 2 by 1.
00:31
2 this a and this a get cancelled 1 r get cancelled so we have as r is equal to minus 1 by root 2 now put in 1 so we get a so a minus a by root 2 is equal to 2 so we get a as minus 2 root 2 so a 7 will be a r to the power 6 which is equal to minus 2 root 2 into minus 1 by root to the power 6 which is equal to minus 2 by 4 root 2 so further simplifying this so we get a7 as equal to minus 1 by 2 root 2.
01:07
Now there's another part to this also.
01:10
Now we have to find the number of terms in the gp in which first term is 16 and the last term is 1 by 64 and r is 1 by 2.
01:22
So first term is given...
