Find the solution of the given initial value problem. $y' - y = 10te^{2t}$, $y(0) = 1$ y(t) = 10t - 10 + 11$e^t$
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The given initial value problem is: yy' = 10te^(2y) + 1 f(10) = 10 + 11e^10 To make it easier to solve, let's rewrite it as: y' = (10te^(2y) + 1)/y f(10) = 10 + 11e^10 Show more…
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