Find the speed of the curve \(\mathbf{r}(t) = \left< 3 \cos(t^2), 3 \sin(t^2), 8t \right>\) at \(t = 5\) Speed =
Added by Joaquin Z.
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The velocity vector is the derivative of the position vector with respect to time. Given that r(t) = (3cos(t^2), 3sin(t^2), 8t), we can find the velocity vector by taking the derivative of each component with respect to t. So, v(t) = (d/dt(3cos(t^2)), Show moreā¦
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