Find the sum for each series. $$\sum_{i=1}^{7}(-1)^{i+1} \cdot i^{2}$$
Added by John F.
Step 1
Step 1:** Expand the series: $$\sum_{i=1}^{7}(-1)^{i+1} \cdot i^{2} = -1 \cdot 1^{2} + 1 \cdot 2^{2} - 1 \cdot 3^{2} + 1 \cdot 4^{2} - 1 \cdot 5^{2} + 1 \cdot 6^{2} - 1 \cdot 7^{2}$$ ** Show more…
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