Find the sum.\\ $\sum_{k=1}^{9} 2^k - 1$
Added by Jacob M.
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The given sum is: \sum_(k=1)^9 2^(k-1) Expanding this sum, we get: 2^0 + 2^1 + 2^2 + 2^3 + 2^4 + 2^5 + 2^6 + 2^7 + 2^8 Show more…
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