Find the surface area of the portion S of the cone z^2 = x^2+y^2 , where z ≥ 0, contained within the cylinder y^2 +z^2 ≤ 81.
Added by Stephanie G.
Step 1
First, we need to find the intersection of the cone and the cylinder. To do this, we can substitute $z^2$ from the cone equation into the cylinder equation: $y^2 + (x^2 + y^2) \leq 81$ Simplifying, we get: $x^2 + 2y^2 \leq 81$ Show more…
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