00:01
Hello, for this question we apply the principle of movements to find a tension t.
00:10
We have a bar, and that bar is held by a rope in which there is tension t.
00:14
That bar is held by a rope in which there is tension t.
00:22
The mass of the bar, the weight of the bar is w.
00:26
And the item that is hanging is also w.
00:33
The angle here is 60.
00:38
So the angle here and the angle here must also be 60.
00:46
It must also be 60.
00:53
So we resolved to find forces perpendicular to our direction.
00:56
So the movement will be due to the forces that are perpendicular to the beam, the perpendicular component of tension also.
01:11
So the molecular component of weight here is weight sign 60, also weight sign 60.
01:22
And for the tension, we look for the angle here, which is 30.
01:28
So that retention sine 30 so applying moments we'll say that for this force the moment is the force given by the distance of the road l plus this force plus its distance from the road since it is halfway in the middle its distance from the point here is l over 2 so we are taking moments about this point p that's so the sum of clockwise moments should be because of the sum of anti -clockwise moments, which is t -sign theta times its distance l.
02:22
So l plus l over 2, w .5l, w, sign 60 equals l t sign 30...