Find the two square complex roots of z = − √ 4 + √ 4 i . Express your answer in polar form and then convert them into rectangular form. roots: θ 1 < θ 2 z 1 = r 1 cis ( θ 1 ) = a 1 + b 1 i Trig form: ( cis ) Standard form: + i z 2 = r 2 cis ( θ 2 ) = a 2 + b 2 i Trig form: ( cis ) Standard form: + i
Added by Ahmad K.
Step 1
Step 1: Convert z to polar form z = -√4 + √4i r = |z| = √((-√4)² + (√4)²) = √(4 + 4) = √8 θ = arctan(Im(z)/Re(z)) = arctan(√4/-√4) = arctan(-1) = -π/4 So, z = √8 cis(-π/4) Show more…
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