Question

Find the value of $a$ that makes $f$ continuous everywhere. $f(x) = \begin{cases} ax + 3 & x < 4 \\ 4x^2 - 3x + 7 & x \ge 4 \end{cases}$

          Find the value of $a$ that makes $f$ continuous everywhere.
$f(x) = \begin{cases} ax + 3 & x < 4 \\ 4x^2 - 3x + 7 & x \ge 4 \end{cases}$

Find the value of a that makes f continuous everywhere.
f(x) = ax + 3 x < 4
4x^2 - 3x + 7 x ≥ 4

Added by Emily T.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

11/07/2023

Step 1

Step 1: To make the function f continuous everywhere, we need to ensure that the two pieces of the function match up at x = 4. Show more…

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Find the value of a that makes f continuous everywhere. f(x)={(ax+3,x<4),(4x^(2)-3x+7,x>=4):} Find the value of a that makes f continuous everywhere. ax +3 x<4 f()=3 4x2 -3x+7 x > 4

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Find the value of $a$ that makes $f$ continuous everywhere. $f(x) = \begin{cases} ax + 3 & x < 4 \\ 4x^2 - 3x + 7 & x \ge 4 \end{cases}$

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