Question

Find the value of \( \lim_{x \to 1} f(x) \) when \( f(x) = \begin{cases} 4x - 3, & x \neq 1, \\ 3, & x = 1, \end{cases} \) if the limit exists.

          Find the value of \( \lim_{x \to 1} f(x) \) when \( f(x) = \begin{cases} 4x - 3, & x \neq 1, \\ 3, & x = 1, \end{cases} \) if the limit exists.

Find the value of limx → 1 f(x) when f(x) = 4x - 3, x ≠ 1,
3, x = 1, if the limit exists.

Added by Gerald W.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Nick Johnson

09/22/2021

Step 1

Since f(x) is defined differently for x=1 and x≠1, we need to consider both cases. Show more…

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Find the value of lim_(x->1)f(x) when f(x)={(4x-3,x!=1,),(3,x=1,):} if the limit exists. Find the value of lim f(x) x1 when 4x-3 x1, x=1 3, if the limit exists.