Find the values of x such that the angle between the vectors \( (4, 1, -1) \), and \( (1, x, 0) \) is 45Β°. (Enter your answers as a comma-separated list.)
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The dot product of two vectors is given by the formula: A Β· B = |A| |B| cos(theta) where A and B are the vectors, |A| and |B| are their magnitudes, and theta is the angle between them. In this case, we have: (4β1-1) Β· (1xO) = |4β1-1| |1xO| Show moreβ¦
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Find the values of $ x $ such that the angle between the vectors $ \langle 2, 1, -1 \rangle $, and $ \langle 1, x, 0 \rangle $ is $ 45^\circ $.
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$$ \begin{array}{l}{\text { Find the values of } x \text { such that the angle between the vectors }} \\ {\langle 2,1,-1\rangle, \text { and }\langle 1, x, 0\rangle \text { is } 45^{\circ} .}\end{array} $$
Find the values of $x$ such that the angle between the vectors $\langle 2,1,-1\rangle,$ and $\langle 1, x, 0\rangle$ is $ 45^{\circ} .$
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