Find the vertices and foci of the ellipse x2 144 y2 169 1...

Transcript

00:01 16 x square plus 9 y square equals to 144 and we make the equation in the form of ellipse so this can be written as here that is here 16 x squared divided by 144 plus 9 y squared divided by 144 that is equal to 1 so here this equation becomes status here x square by 9 plus y square by y squared by 16 and this is equal to 1 so here this can also be written as x square by 3 whole square plus y square by 4 whole a square equals to 1 and we know that the extended equation of ellipse here that is x square by a square plus y a square by b a square equals to 1 this is the standard form of equation so here a equals to 3 and b equals to here 4 and this is here see that here that is b greater than a so here major major axis is vertical measure axis is vertical so here x intercept that is minus 30 and 3 and 3 and y intercept here that is 0 minus 4 and 0 4 this measure so and we also know that that is c squared equals to here b is greater so this becomes b a square minus a square and this becomes here that is 16 minus 9 that is here 7 and c equals to root under 7 so here fokey fokey equals to 0 minus root 7 and 0 root 7.

02:03 So we have to draw the graph here.

02:07 So we take this is x -axis and this is y -axis and this is negative direction of y and this is negative direction of x -dax.

02:16 We have to draw here the graph.

02:19 So we take the point on the here.

02:23 So this is taken to be 0 and here point is so this point 1, this is 2, this is 3 and this is here 4.

02:34 This is minus 1, this is here.

02:38 This is taken to minus 1, minus 2, minus 3 and this is here minus 4.

02:44 So this graph will be extended here...