00:01
Since they want you to use shells, this problem is kind of tricky.
00:04
So we have y equals 4 minus 2x, which i really care about.
00:11
I'm glad they gave me that because i can tell right now that my y intercepts, my y intercept is going to be at 4 .04.
00:20
I also need this 0 -0 because we are revolving around the x -axis.
00:25
But in order to use shells, what i need is these links.
00:31
As i revolve around the x -axis.
00:35
So what that tells me is i need to solve this equation for x.
00:41
So just writing that over here, i would subtract 4 over is equal to negative 2x, and then divide everything by negative 2.
00:49
I would have negative 1 half y plus 2 is equal to x.
00:55
So in the show method, it's basically a lateral area of a cylinder is 2 pi r h.
01:03
If you look closely at this problem then, well, 2 pi is a concept, so it's right in front.
01:08
My bounds are 0 and 4...
