00:01
I think the way i would approach this problem is to examine with the graph, you have the squared root of x, and then you also have y equals x over 2, which is the same thing as writing one -half x.
00:19
So it's a linear equation with a slope of one -half, and you can set them equal to each other to find where they intersect.
00:27
And what do i mean by that is you can square both sides, so you'd have x equals one -fourth x squared.
00:36
And then from this, maybe multiply both sides by four, just to make a little bit easier.
00:42
So if you subtract the x squared over and then factor out the x, 4 minus x, you can actually see that they intersect at 0 and 4.
00:54
And we're revolving along the line y equals 4, which kind of confirms that.
01:01
Well, i don't think i have them in the right spot because the square to four would be two.
01:08
So yeah, this lower revolving round is even higher.
01:11
But no matter what's going to be the washer method from zero to four of the upper function squared minus the lower function squared...