00:02
Well, since they give me x equals 0 and x equals 2, i think i would go to the problem like this.
00:08
Now, first of all, i'd want to make sure that we're good to do this problem, like 2 over 1 plus x, that we have a vertical asymptote at x equals negative 1.
00:20
So i guess i just want to make sure that when you plug in 0, you are getting a, i guess, a halfway decent problem.
00:29
Same thing with if you plugged in two, you'd get two -thirds.
00:33
So yeah, i think we're good to do this problem and revolve it around the line, y equals six.
00:40
So i think what i would do is just the washer method.
00:44
And i'm going to admit that i'm going to use a calculator because the area of the circle is pi r squared, that i would set up this volume as doing the function that's further away...