Find the work done by a force of 6N acting in the direction 3i+5j+√2k on an object 4 m from (0,0,0) to (0,4,0).
Added by Douglas W.
Step 1
This can be found by subtracting the initial position vector from the final position vector: Displacement vector = (0-0)i + (4-0)j + (0-0)k Displacement vector = 0i + 4j + 0k Displacement vector = 4j Show more…
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