find the x and y interecpts of the equation (if an answr does not exist enter DNE) y=x^2-6
Added by Kathleen V.
Step 1
\[ 0 = x^2 - 6 \] Add 6 to both sides: \[ x^2 = 6 \] Take the square root of both sides: \[ x = \pm \sqrt{6} \] So, the x-intercepts are \( (\sqrt{6}, 0) \) and \( (-\sqrt{6}, 0) \). --- Show more…
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