00:01
All righty, so here we have a nice z score exercise.
00:06
Find the z score corresponding to the given value and use the z score to say whether it's unusual.
00:12
And so we've got a test score of 92 .6, so x is 92 .6.
00:22
And the test has a mean, so a population mean of 75, and a sigma, a standard deviation of 11.
00:33
Great.
00:33
So there's that.
00:34
Now, what we want to do is convert this to a z score.
00:40
And the z score formula is given as x minus mu all over sigma.
00:46
So we substitute in our values, 92 .6 minus 75 over 11.
00:53
And that's going to give us 1 .6.
00:56
And we are told that a score is to be considered unusual if it's z score is less than negative 2 or greater than 2.
01:06
And sure enough, 1 .6 is not greater than 2 or less than negative 2.
01:11
So we'd say it's unusual...