Find y'' by implicit differentiation. 4x3 + 3y3 = 5
Added by William L.
Step 1
The derivative of 4x^3 is 12x^2. The derivative of 3y^3 is 9y^2 * y', because of the chain rule (we're differentiating with respect to x, not y). The derivative of 5 is 0. So, the first derivative of the equation is 12x^2 + 9y^2 * y' = 0. Show more…
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