00:01
Hello, here i have to find y prime.
00:03
Let's do this.
00:03
It's given that x power by y equals to y power by x.
00:07
First, let's find d of x power by y with respect to d x.
00:13
Let's do this.
00:15
Hello, here i have to find y.
00:17
Hello, here i have to find y.
00:19
Find the derivative, let's consider the function of x being, or just f, being x power by y.
00:27
And now let's take natural logarithm of both sides, natural logarithmof x becomes y times natural logarithm of x and now let's take the derivative here 1 over f times 1 over times f prime equals to that becomes equal to the form that is y prime times natural logarithmicl of x plus y over x and now let's simplify this, it means that f prime equals to f times y prime natural algorithm of x plus y over x, which equals for the following, that's x power by fai times y prime, like natural logarithm of x plus y over x...