Question

Tag Index (2 bits) Address (4 bits) 1 10 1 Block offset 2 Index Valid Tag Data 0 1 2 3 8 8 = Mux 8 Hit Data

          Tag
Index (2 bits)
Address (4 bits)
1
10
1
Block offset
2
Index Valid Tag
Data
0
1
2
3
8
8
=
Mux
8
Hit
Data

Added by Daniel M.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Aman Gupta

Step 1

Since the cache is 16K-byte and the block size is 32 bytes, we can calculate the number of blocks as follows: Number of blocks = Cache size / Block size = 16K-byte / 32 bytes = 512 blocks Show more…

Show all steps

Thanks for your feedback!

For a 16K-byte, direct-mapped cache, suppose the block size is 32 bytes. Draw a cache diagram indicating the block size, number of blocks, and address field decomposition (block offset, index, and tag bit width) assuming a 32-bit memory address. Diagram should look like this: Tag (10 bits) Index (2 bits) Block offset (4 bits) Address (16 bits) Block 0 Index Valid Tag Data 0 1 2 3 Mux 8 Hit Data