for a village three power plant will be selected between steam power plant hydroelectric power p

Hello students, let's say this question. In the question, average load is given 164 .75 kilowatt

In this question, you look at basically the energy produced by in China, right, in 2014. That's

According to the question in part A, the actual energy required is equal to the capacity factor

First of all, let us find the maximum power that can be extracted, which is row v .g times delta

So, let us start with the concept which we are going to use here for this question. So, geotherm

Question

For a village, three power plants will be selected between Steam power plant, hydroelectric power plant, diesel power plant, and pump storage hydroelectric power plant. For this village, the annual load curve given below (Table-1). For the Main Power plant, Booster-Auxiliary-Power Plant, and Peak Power Plant, the power they need to provide is given below (Table-2). Power plants must be selected to provide the lowest cost for 1 kWh output energy. Select the Main Power Plant, Booster-Auxiliary-Power Plant, and Peak Power Plant between these 4 types of power plants, based on unit costs. Calculate the cost for each of these chosen 3 power plants at 1 kWh output energy. After creating this system, calculate the cost of this system for 1 kWh output. Create a table like Table-3. P.S: For the pump storage hydroelectric power plant, the efficiency of pumping up is 92% (Pump is operating) and the efficiency of pumping down is 95% (Generator is Operating) Unit Steam Diesel P.P P.P $/kW 350 200 % 10 15 $/Ton 1000 3500 Kcal/k 8250 10200 g % 30 25 Table-1 Hydroelectric P.P 500 18 Pump Storage H.P.P 800 13 Unit Cost of Plant Total Capital Expenditure Fuel Cost Lower Heating Value of Fuel Efficiency 1.2 Peak Power Plant 0.8 x10 Power[MW] 0.6 0.4 Booster-Auxiliary- P.P Main Power Plant 0.2 0 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 x8760 Time[hours] Table-2 Chosen Plant Plants Cost at 1 kWh ? ? ? ? Table-3 Main Power Plant ? ? ? ? Booster-Auxiliary-Power Plant Peak Power Plant Created System

For a village, three power plants will be selected between Steam power plant, hydroelectric power plant, diesel power plant, and pump storage hydroelectric power plant. For this village, the annual load curve given below (Table-1). For the Main Power plant, Booster-Auxiliary-Power Plant, and Peak Power Plant, the power they need to provide is given below (Table-2).

Power plants must be selected to provide the lowest cost for 1 kWh output energy. Select the Main Power Plant, Booster-Auxiliary-Power Plant, and Peak Power Plant between these 4 types of power plants, based on unit costs. Calculate the cost for each of these chosen 3 power plants at 1 kWh output energy. After creating this system, calculate the cost of this system for 1 kWh output. Create a table like Table-3.

P.S: For the pump storage hydroelectric power plant, the efficiency of pumping up is 92% (Pump is operating) and the efficiency of pumping down is 95% (Generator is Operating)

Unit
Steam Diesel P.P P.P $/kW 350 200 % 10 15 $/Ton 1000 3500 Kcal/k 8250 10200 g % 30 25 Table-1
Hydroelectric P.P 500 18
Pump Storage H.P.P 800 13
Unit Cost of Plant Total Capital Expenditure Fuel Cost Lower Heating Value of Fuel Efficiency
1.2
Peak Power Plant
0.8 x10 Power[MW] 0.6 0.4
Booster-Auxiliary- P.P
Main Power Plant
0.2
0 0
0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 x8760 Time[hours]
Table-2
Chosen Plant
Plants Cost at 1 kWh ? ? ? ? Table-3
Main Power Plant
? ? ? ?
Booster-Auxiliary-Power Plant Peak Power Plant Created System

for a village three power plant will be selected between steam power plant hydroelectric power plantdiesel power plant and pump storage hydroelectric power plantfor this village annual load 97678

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