Question

For an electron in a box of length 1 angstrom ( 1 angstrom = 10-10 m) , A) Calculate the separation between the two lowest energy levels. B) Calculate the wavelength corresponding to the transition between these two levels. Given the mass of an electron = 9.10939 x 10-31 kg, Plank's constant (h) = 6.626 x 10-34 Js

          For an electron in a box of length 1 angstrom ( 1 angstrom =
10-10 m) ,
A) Calculate the separation between the two lowest energy
levels.
B) Calculate the wavelength corresponding to the transition
between these two levels.
Given the mass of an electron = 9.10939 x 10-31 kg, Plank's
constant (h) = 6.626 x 10-34 Js
        
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Added by Vanesa S.

Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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For an electron in a box of length 1 angstrom ( 1 angstrom = 10-10 m) , A) Calculate the separation between the two lowest energy levels. B) Calculate the wavelength corresponding to the transition between these two levels. Given the mass of an electron = 9.10939 x 10-31 kg, Plank's constant (h) = 6.626 x 10-34 Js
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For an electron in a box of length 1 angstrom ( 1 angstrom = 10-10 m) , A) Calculate the separation between the two lowest energy levels. B) Calculate the wavelength corresponding to the transition between these two levels. Given the mass of an electron = 9.10939 x 10-31 kg, Plank's constant (h) = 6.626 x 10-34 Js

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Question 8 For an electron in a box of length 1 angstrom ( 1 angstrom = 10^-10 m), A) Calculate the separation between the two lowest energy levels. B) Calculate the wavelength corresponding to the transition between these two levels. Given the mass of an electron = 9.10939 x 10^-31 kg, Plank's constant (h) = 6.626 x 10^-34 Js

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Consider a free electron confined in a 1-dimensional box of 1 nm length. Calculate the wavelength of a photon that needs to be absorbed by the electron so that it makes a transition from the ground state to the first excited state. Physical Constants: h = 6.626 !! 10^-34 J s me = 9.109 !! 10^-31 kg c = 2.998 !! 10^8 m/s 1 nm = 10^-9 m

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Transcript

-
00:02 The length is 1am strong that is 10 to the power minus 10 meter.
00:08 Now delta e, we can calculate e2 minus e1.
00:14 That will be 2 to the power 2 square h square by 8 ml square minus 1 square to the power 8ml square because e is equal to n square h square 8m l square so that will be equal to 4 minus 1 h square by 8m l square so to simplifying this we'll get 3h square upon 8m l square putting the values 3 into 6 .63 into 10 to the power minus 34 whole square divided by 8 into 9.
01:01 0 .11 into 10 to the power minus 31 into 10 to the power minus 10 whole square.
01:11 So after simplifying this, we will get delta e is equal to 1 .81 into 10 to the power minus 17 joules...
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