For buffer solution for miniprep, you make 250mL of a...

For buffer solution for miniprep, you make 250mL of a solution with the final concentration of the reagents: 250µM EDTA and 5% NaCl. The following stocks used to make the solution. 0.5M EDTA liquid solution NaCl powder (MW = 58.44g/mol) How much reagent do you use w/ units? a) EDTA ____ b) NaCl ____

Transcript

00:01 So here, according to the information given in the question, two solutions are being made here.

00:07 And these solutions basically have edta and edta which has a concentration of 250 micromolar.

00:16 And it should also have another compound which is sodium chlorator nscl with a concentration of 5 % and the final volume of the solution would be equal to 250 mill or ml.

00:32 And it is also given that a stock solution is being present and the stock solution is basically the stock solution of edta and the concentration of the stock solution is 0 .5 molar and they have also given the mw or we can see the molecular weight of sodium chloride which is 58 .44 gram per mole and with this information already given we have to basically figure out that how much stock solution is needed to make desired concentration.

01:02 So first let's calculate for edta using the formula v1s1 equals to v2s2.

01:11 Here this v1 basically shows the volume of the stock which is needed and this is basically unknown.

01:18 We have to calculate how much volume of stock is needed in order to prepare the desired solution.

01:23 V2 basically shows the final volume of the solution which is given as 250 ml here and s1 shows the concentration of the stock solution and the concentration of the stock solution is given as 0 .5 and s2 is the concentration of the final solution which is also given which is 250 micro molar.

01:44 So basically we need to basically convert certain values here because when we talk about that 1 molar is equal to 1 ,000 micromolar and if we'll convert this 0 .5 molar into micromolar, we'll multiply it by 1 ,000 and we'll get a value of 500 micromolar.

02:04 So we have converted this value into 500 micromolar.

02:09 And if we put this into formula, v1 is unknown, so it will be v1 only...

Question

For buffer solution for miniprep, you make 250mL of a solution with the final concentration of the reagents: 250µM EDTA and 5% NaCl. The following stocks used to make the solution. 0.5M EDTA liquid solution NaCl powder (MW = 58.44g/mol) How much reagent do you use w/ units? a) EDTA b) NaCl

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