00:01
Okay, so let's get started with part a of our exercise.
00:05
Well, here we are going to show that limit as n goes to infinity of hn of x is equal to h of x equal to the absolute value of x.
00:25
How can we show this? this is the point wise convergence.
00:29
Well this is pretty easy.
00:31
Let's consider the absolute value of hn of x minus h of x.
00:39
Well, this guy here is the absolute value of the square root of x squared plus one over n minus the absolute value of x.
00:49
Okay, now let's observe that this one is clearly greater than or equal to this guy.
00:56
So we can write it as square root of x squared plus one over n minus the absolute value of x.
01:04
And this guy here is less than or equal to one over n.
01:10
Perfect.
01:11
This shows that sup as x belongs to r of the absolute value of hn of x minus h of x.
01:22
Well, this one is equal to one over n and clearly it goes to zero as n goes to infinity.
01:33
So we have shown that hn converges uniformly to h.
01:41
Therefore, we also have the point wise convergence.
01:45
Easy.
01:46
Now, okay.
01:49
Well, part b of our exercise...