Question

For each situation in Exercise 7.9, find an interval that contains (approximately or exactly) 99.73 percent of all the possible sample means. In which cases must we assume that the population is normally distributed? Why?a. μ = 10, σ = 2, n = 25b. μ = 500, σ = .5, n = 100c. μ = 3, σ = .1, n = 4d. μ ± = 100, σ = l, n = 1,600

Name: for each situation in exercise 79 find an interval that contains approximately or exactly 9973 percent of all the possible sample means in which cases must we assume that the population is n 13732
Uploaded: 2022-09-13T09:01:45-08:00
Duration: 6 min 42 s
Channel: Adi S
Description: for each situation in exercise 79 find an interval that contains approximately or exactly 9973 percent of all the possible sample means in which cases must we assume that the population is n 13732

          For each situation in Exercise 7.9, find an interval that contains (approximately or exactly) 99.73 percent of all the possible sample means. In which cases must we assume that the population is normally distributed? Why?a. μ = 10, σ = 2, n = 25b. μ = 500, σ = .5, n = 100c. μ = 3, σ = .1, n = 4d. μ ± = 100, σ = l, n = 1,600

Added by Tina S.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Adi S

09/13/2022

Step 1

$\sigma = 2$, $n = 25$ Standard error = $\frac{\sigma}{\sqrt{n}} = \frac{2}{\sqrt{25}} = 0.4$ b. $\sigma = 0.5$, $n = 100$ Standard error = $\frac{\sigma}{\sqrt{n}} = \frac{0.5}{\sqrt{100}} = 0.05$ c. $\sigma = 0.1$, $n = 4$ Standard error = Show more…

Show all steps

Thanks for your feedback!

For each situation in Exercise 7.9, find an interval that contains (approximately or exactly) 99.73 percent of all the possible sample means. In which cases must we assume that the population is normally distributed? Why?a. μ = 10, σ = 2, n = 25b. μ = 500, σ = .5, n = 100c. μ = 3, σ = .1, n = 4d. μ ± = 100, σ = l, n = 1,600