For \( f(x)=\sqrt{x-6} \), what is the vertex of \( f(x) \) after being horizontally dilated by a factor of 2 ? Write your answer as an ordered pair. Do not include spaces.
Added by Charles F.
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The vertex of this function occurs when the expression inside the square root is zero. Set \( x - 6 = 0 \) to find the x-coordinate of the vertex: \[ x = 6 \] Show more…
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