Question

For $k(x) = (2x - 1)(x - 3)(-x^2 - 2)$, find the derivative of $k(x)$ using the product rule. Select the correct answer below: $-2x^4 + 7x^3 - 7x^2 + 10x - 6$ $-8x^3 + 21x^2 - 14x + 14$ $-4x$ $-2x + 3$ $2x^3 + 9x - 5$

Name: for kx 2x 1x 3 x2 2 find the derivative of kx using the product rule select the correct answer below 2x4 7x3 7x2 10x 6 8x3 21x2 14x 14 4x 2x 3 2x3 9x 5 82646
Uploaded: 2022-06-09T03:38:36-08:00
Duration: 3 min 58 s
Channel: Ma. Theresa Alin
Description: for kx 2x 1x 3 x2 2 find the derivative of kx using the product rule select the correct answer below 2x4 7x3 7x2 10x 6 8x3 21x2 14x 14 4x 2x 3 2x3 9x 5 82646

          For $k(x) = (2x - 1)(x - 3)(-x^2 - 2)$, find the derivative of $k(x)$ using the product rule.

Select the correct answer below:
$-2x^4 + 7x^3 - 7x^2 + 10x - 6$
$-8x^3 + 21x^2 - 14x + 14$
$-4x$
$-2x + 3$
$2x^3 + 9x - 5$

for kx 2x 1x 3 x2 2 find the derivative of kx using the product rule select the correct answer below 2x4 7x3 7x2 10x 6 8x3 21x2 14x 14 4x 2x 3 2x3 9x 5 82646

Added by Rafael S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Ma. Theresa Alin

06/09/2022

Step 1

First, let's expand the expression for $k(x)$. $k(x) = (2x - 1)(x - 3)(-x^2 - 2)$ Multiply the first two factors: $(2x - 1)(x - 3) = 2x(x) + 2x(-3) - 1(x) - 1(-3)$ $= 2x^2 - 6x - x + 3$ $= 2x^2 - 7x + 3$ Now, multiply this result by the third factor: $k(x) = Show more…

Show all steps

Thanks for your feedback!

For $k(x) = (2x - 1)(x - 3)(-x^2 - 2)$, find the derivative of $k(x)$ using the product rule. Select the correct answer below: $-2x^4 + 7x^3 - 7x^2 + 10x - 6$ $-8x^3 + 21x^2 - 14x + 14$ $-4x$ $-2x + 3$ $2x^3 + 9x - 5$