00:01
Hi students, here in this question we have a circuit and we have a battery and two resistors.
00:07
So, here the power supply supplies 9 volt to these two resistors.
00:12
Okay, now there are two resistors of r1 is equal to 10 ohm and r2 of 20 ohm.
00:19
Now, we want to find out the voltage drop across each resistor.
00:23
So, before going to the voltage drop, first of all we want to find out the current.
00:30
So, the total resistance, total resistance for series connection.
00:43
So, in the circuit it is clear that r1 and r2 are connected in series.
00:47
So, r is equal to r1 plus r2.
00:54
So, the value of r will be 10 plus 20 is equal to 30 ohm.
01:01
Now, we have ohm's law that is v is directly proportional to i or v is equal to i into r that implies i is equal to v by r.
01:15
Here v is 9 volt and r is the total resistance that is 30 ohm.
01:20
So, 9 divided by 30 is equal to 0 .3 ampere.
01:27
So, the current in the circuit is 0 .3 ampere.
01:33
So, the current this is a serial circuit.
01:36
So, the current passing through r1 is 0 .3 ampere and r2 also i is equal to 0 .3 ampere...