For the diprotic weak acid H2A, Ka1 = 3.6 × 10^-6 and Ka2 = 5.1 × 10^-9. What is the pH of a 0.0450 M solution of H2A? What are the equilibrium concentrations of H2A and A2- in this solution? PH= [H2A]= M [A2-]= M
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Step 1
First, we need to find the concentration of H₃O⁺ ions in the solution. Since H₂A is a diprotic weak acid, it will donate two protons (H⁺) in two steps. We will consider the first ionization step: H₂A ⇌ H⁺ + HA⁻ Ka1 = [H⁺][HA⁻] / [H₂A] Show more…
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