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This problem says for the following exercises, we are considering a special six -sided die with faces that are labeled with a number in a letter.
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And we have 1a, 1b, 2a, 2c, 4a, and 4e.
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And we're going to roll the die once, and we're asked for three probabilities.
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First, the probability of rolling a 1 or a 2.
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And here we have two possibilities for a 1 and 2 possibilities for a 2.
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So that's 4 total successes out of the total 6 possibilities since it's a 6 -sided die.
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4 out of 6 sets up our original probability.
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And then we can divide numerator and denominator by 2 to give us the simplified probability of 2 thirds.
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Next for 19, we want a probability of a 4 or b.
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And we have two possibilities for 4 and then one possibility for b.
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So that's two successes here possible and one success here.
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So that's 3 successes possible out of the total 6.
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And again, we can simplify this time by dividing by 3.
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Which gives us the simplified fraction form probability of one half...