Question

For the following problems, the units of a variable are given along with the units for a function (or two functions). Give the units of each definite integral. (a) If x is in ""seconds"" and f(x) is in ""feet/second"" then $int_a^b f(x) dx$ is in $circ$ feet/sec$^2$ $circ$ feet/sec $circ$ feet $circ$ feet-sec (b) If t is in ""seconds"" and g(t) is in ""feet/seconds$^2$"" then $int_a^b g(t) dt$ is in $circ$ feet/sec$^2$ $circ$ feet/sec $circ$ feet $circ$ feet-sec (c) If x is in ""days"" and f(x) is in ""degrees F"" then $int_a^b f(x) dx$ is in $circ$ days $circ$ (degrees F)/day $circ$ degrees F $circ$ (degrees F)-days (d) If x is in ""hours"" and g(x) is in ""kilowatts"" then $int_a^b g(x) dx$

          For the following problems, the units of a variable are given
along with the units for a function (or two functions). Give the
units of each definite integral.
(a) If x is in ""seconds"" and f(x) is in ""feet/second"" then $int_a^b f(x) dx$
is in
$circ$ feet/sec$^2$
$circ$ feet/sec
$circ$ feet
$circ$ feet-sec
(b) If t is in ""seconds"" and g(t) is in ""feet/seconds$^2$"" then $int_a^b g(t) dt$
is in
$circ$ feet/sec$^2$
$circ$ feet/sec
$circ$ feet
$circ$ feet-sec
(c) If x is in ""days"" and f(x) is in ""degrees F"" then $int_a^b f(x) dx$
is in
$circ$ days
$circ$ (degrees F)/day
$circ$ degrees F
$circ$ (degrees F)-days
(d) If x is in ""hours"" and g(x) is in ""kilowatts"" then $int_a^b g(x) dx$

For the following problems, the units of a variable are given
along with the units for a function (or two functions). Give the
units of each definite integral.
(a) If x is in ""seconds"" and f(x) is in ""feet/second"" then inta^b f(x) dx
is in
circ feet/sec^2
circ feet/sec
circ feet
circ feet-sec
(b) If t is in ""seconds"" and g(t) is in ""feet/seconds^2"" then inta^b g(t) dt
is in
circ feet/sec^2
circ feet/sec
circ feet
circ feet-sec
(c) If x is in ""days"" and f(x) is in ""degrees F"" then inta^b f(x) dx
is in
circ days
circ (degrees F)/day
circ degrees F
circ (degrees F)-days
(d) If x is in ""hours"" and g(x) is in ""kilowatts"" then inta^b g(x) dx

Added by Michael C.

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