Question

For the following reaction, 5.95 grams of ammonia are allowed to react with 18.4 grams of oxygen gas. 4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g) What is the FORMULA for the limiting reagent? What is the maximum mass of nitrogen monoxide that can be formed? in grams What mass of the excess reagent remains after the reaction is complete? in grams

Name: for the following reaction 595 grams of ammonia are allowed to react with 184 grams of oxygen gas 4 nh3g 5 o2g 4 nog 6 h2og what is the formula for the limiting reagent what is the maximum m 88406
Uploaded: 2022-09-21T10:28:39-08:00
Duration: 3 min 9 s
Channel: Adi S
Description: for the following reaction 595 grams of ammonia are allowed to react with 184 grams of oxygen gas 4 nh3g 5 o2g 4 nog 6 h2og what is the formula for the limiting reagent what is the maximum m 88406

          For the following
reaction,  5.95 grams
of  ammonia are allowed to react
with  18.4 grams
of  oxygen gas.
4 NH3(g)
+  5 O2(g)   4 NO(g)
+ 6 H2O(g) 
What is the  FORMULA for the
limiting reagent?
What is the maximum mass of  nitrogen
monoxide that can be formed?    in
grams
What mass of the excess reagent remains after the reaction is
complete?   in grams

Added by Jeremy C.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adi S

09/21/2022

Step 1

95 g Molar mass of NH3 = 17 g/mol Moles of NH3 = 5.95 g / 17 g/mol = 0.35 mol Show more…

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For the following reaction, 5.95 grams of ammonia are allowed to react with 18.4 grams of oxygen gas. 4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g) What is the FORMULA for the limiting reagent? What is the maximum mass of nitrogen monoxide that can be formed? in grams What mass of the excess reagent remains after the reaction is complete? in grams