00:05
In this question we have given graph of a function is follows.
00:11
Using this graph we have to find some value.
00:15
In part a we have to find the limit x tends to 1 f of x.
00:23
As we know there, limit of a function will exist if and only if the left -hand limit and the right -hand limit of a function is safe.
00:32
So for finding the limit of a function at x is equal to 1 first we move in the graph from the left hand side near 1 so we get value of y is equal to 2 when x is equal to 1 so limit x tends to minus 1 f f is equal to 2 here minus sign indicates the left hand side limit now in the same manner if we move from the right side near x is opposed to 1 again we get y is equal to 2.
01:10
So limit x tends to 1 plus epaulet is equal to 2.
01:19
Here plus sign indicates right hand side limit.
01:23
Since both the limits are same therefore limit extends to 1 fopax is equal to 2.
01:31
Now in part b we have to find limit x tends to 3 minus x here minus that indicates the left hand side limit so for finding left and side limit we will move our pencil from left side near to the point x is equals to 3 so when we reach at x is equals to 3 from the left hand side we will get the value of y as 1 so it will be equals to 1.
02:04
In part c, we have to find limit x tends to 3 plus f of x.
02:12
So here, plus sign indicates the right hand limit.
02:16
So in a graph we move from the right hand side near the point x is equal to 3.
02:23
We get the value of y is equal to 4...